haileekovach
contestada

A small bar of gold whose density is 19.3 g/cm³, displaces 80 cm³ of water when dropped into a beaker. What's the mass of the bar of gold?

Respuesta :

znk

Answer:

[tex]\boxed{\textbf{1.54 kg}}[/tex]

Explanation:

D = m/V

Data:

V = 80 cm³

D = 19.3 g/cm³

Calculation:

[tex]\begin{array}{rcl}19.3 & = & \dfrac{m}{80}\\\\m & = & 19.3 \times 80\\& = & \text{1540 g}\\& = & \textbf{1.54 kg}\end{array}\\\text{The mass of the bar of gold is $\boxed{\textbf{1.54 kg}}$}[/tex]

CintiaSalazar

Taking into account the definition of density, the mass of the bar of gold is 1544 grams.

But first you must know the definition of density. Density is defined as the property that matter, whether solid, liquid or gas, has to compress into a given space.

In other words, density is a quantity that allows us to measure the amount of mass in a certain volume of a substance.

Then, the expression for the calculation of density is the quotient between the mass of a body and the volume it occupies:

[tex]density= \frac{mass}{volume}[/tex]

In this case, you know that:

  • density= 19.3 [tex]\frac{g}{cm^{3} }[/tex]
  • mass= ?
  • volume 80 cm³

Replacing in the definition of density:

[tex]19.3\frac{g}{cm^{3} } =\frac{mass}{80cm^{3} }[/tex]

Solving:

mass= 19.3 [tex]\frac{g}{cm^{3} }[/tex]× 80 cm³

mass=  1544 grams

In summary, the mass of the bar of gold is 1544 grams.

Learn more about density:

  • brainly.com/question/952755?referrer=searchResults
  • brainly.com/question/1462554?referrer=searchResults

Otras preguntas