Find the maximum potential difference between two parallel conducting plates separated by 1.18 cm of air, given the maximum sustainable electric field strength in air to be 3.0\times 10^6~\text{V/m}3.0×10 ​6 ​​ V/m.

Respuesta :

Answer:

The maximum potential difference between two parallel conducting plates is 35400V

Explanation:

The potential difference between two conductive plates is determined by the following formula:

V=E*d Equation (1)

Where,

V: The potential difference in volts (V)

E: The electric field in V/m

d : Distance between the plates (m)

Known data:

[tex]E=3*10^{6} \frac{V}{m}[/tex]

D=1.18cm, 1m=100cm, D=1.18cm*1m/100cm

[tex]d=1.18*10^{-2} m[/tex]

We replace the information known in the equation (1):

[tex]V=3*10^{6} *1.18*10^{-2}[/tex]

[tex]V=3.54*10^{4}[/tex]

V=35400V