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The length of a rectangle is 5 inches more than its width, x. The area of a rectangle can be represented by the equation x 2 + 5x = 300. What are the measures of the width and the length? Width = a0 inches Length = a1 inches

Respuesta :

Answer:

Width = 15 inches             Length = 20 inches

Step-by-step explanation:

The area of a rectangle is calculated using the following formula.

[tex]A = Lx[/tex]   (1)

Where L is the length and x is the width of the rectangle

In this case we know that the length of the rectangle is 5 inches greater than its width. This means that:

[tex]L = x + 5[/tex]   (2)

Also The area of a rectangle can be represented by the equation [tex]x^2 + 5x = 300[/tex]

so to find the width x we solve the equation

[tex]x^2 + 5x -300=0[/tex]   (3)

For an equation of the form [tex]ax ^ 2 + bx + c = 0[/tex] the quadratic formula is:

[tex]x=\frac{-b\±\sqrt{b^2-4ac}}{2a}[/tex]

In this case note that:

[tex]a=1\\b=5\\c=-300[/tex]

Then:

[tex]x=\frac{-5\±\sqrt{(5)^2-4(1)(-300)}}{2(1)}[/tex]

[tex]x=\frac{-5\±\sqrt{25+1200}}{2}[/tex]

[tex]x=\frac{-5\±\sqrt{1225}}{2}[/tex]

[tex]x=\frac{-5\±35}{2}[/tex]

[tex]x_1=\frac{-5+35}{2}[/tex]  →  [tex]x_1=15[/tex]

[tex]x_2=\frac{-5-35}{2}[/tex]  →   [tex]x_2=-20[/tex]

We take the positive solution [tex]x=15\ in[/tex]

Now we use equation (2) to find L

[tex]L = x + 5[/tex]

[tex]L = 15 + 5[/tex]

[tex]L = 20\ in[/tex]

Answer:

width = 15 inches

Length = 20 inches

That's your answer!!