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3. The electric field of a sinusoidal electromagnetic wave has an amplitude of 5.0 V/m. How much radiation energy passes through a 1.5 m2 window perpendicular to the wave during one hour? a) 258 J b) 459 J c) 351 J d) 531 J e) 179 J

Respuesta :

Answer:

e) [tex] 179[/tex] J

Explanation:

[tex]E_{o}[/tex] = Magnitude of electric field = 5 V/m

[tex]A[/tex] = Area of window = 1.5 m²

[tex]c[/tex] = speed of electromagnetic wave = 3 x 10⁸ m/s

[tex]\Delta t[/tex] = time interval = 1 h = 3600 sec

radiation energy is given as

[tex]U = (0.5)\epsilon _{o}E_{o}^{2}cA\Delta t[/tex]

[tex]U = (0.5)(8.85\times 10^{-12})(5)^{2}(3\times 10^{8})(1.5)(3600)[/tex]

[tex]U = 179[/tex] J

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