Answer:
0.2 m/s^2
Explanation:
Maximum distance, h = 19.5 m
initial speed, u = 2.80 m/s
final speed, v = 0 m/s
Let the gravitational acceleration is a.
Use third equation of motion
[tex]v^{2}=u^{2}-2\times a\times h[/tex]
[tex]0^{2}=2.80^{2}-2\times a\19.5[/tex]
[tex]2\times a\19.5=7.84[/tex]
a = 0.2 m/s^2
Thus the gravitational acceleration on the exoplanet is 0.2 m/s^2
