Answer:
The minimum mass of ethane that could be left over by the chemical reaction is zero.
Explanation:
[tex]2C_2H_6+7O_2\rightarrow 4CO_2+6H_2O[/tex]
Moles of ethane = [tex]\frac{23.0 g}{30 g/mol}=0.7666 mol[/tex]
Moles of oxygen gas :
[tex]\frac{147.0 g}{32 g/mol}=4.59375 mol[/tex]
Since, 2 moles of ethane gas react with 7 moles of oxygen gas.
Then 0.7666 mol of ethane gas will react wit:
[tex]\frac{7}{2}\times 0.7666 mol=2.6831 mol[/tex]
This means that ethane gas is in limited amount.hence ethane is a limiting reagent. Where as oxygen in present in excessive amount.
All the moles ethane gas will go under combustion reaction leaving zero moles behind.
