Answer:
Δp = 3.31 × 10⁻²⁴ kg.m/s
Explanation:
Given:
Electron is confined to a space of, Δx = 10⁻¹⁰ m
According to the Heisenberg uncertainty principle, we have
[tex]\Delta p=\frac{h}{2\Delta x}[/tex]
where, h is the plank's constant = 6.626 × 10⁻³⁴ J.s
Δp is the uncertainty in the momentum
on substituting the respective values, we get
[tex]\Delta p=\frac{6.626\times10^{-34}}{2\times10^{-10}}[/tex]
or
Δp = 3.31 × 10⁻²⁴ kg.m/s
