Respuesta :
Explanation:
1) The expression of concentration that provides the moles of solute per kilograms of solvent is Molality.
Number of moles = n
[tex]n=\frac{\text{Mass of solute}}{\text{Molar mass of solute}}[/tex]
[tex]Molarity=\frac{n}{\text{Mass of solvent(kg)}}[/tex]
2) A solution is made up of 0.15 grams of sodium chloride in 1 liter of water. For this solution, the solvent is water.
Solution is an aqueous mixture of solute and solvent in which mass of solute is always less than the mass of solvent.
3) A solution is made up of 0.15 grams of sodium chloride in 1 liter of water. For this solution, the solute is sodium chloride.
Solution is an aqueous mixture of solute and solvent in which mass of solute is always less than the mass of solvent. This is because sodium chloride is present very less amount in its aqueous solution.
4) If you place 5 moles of sodium chloride and 4 moles of sucrose into 11 moles of water, the mole fraction of sodium chloride would be 0.25.
Mole fraction is defined as ratio of moles of component to total moles of all the components in the solution.
[tex]\chi_i=\frac{n_i}{\sum n_1+n_2..n_i}[/tex]
(Mole fraction of the i component)
5) A way to express concentration that provides the moles of solute per liter of solution is molarity.
[tex]n=\frac{\text{Mass of solute}}{\text{Molar mass of solute}}[/tex]
[tex]Molarity=\frac{n}{\text{Volume of solution(L)}}[/tex]
Answer:
- The expression of concentration that provides the moles of solute per kilograms of solvent is molality.
- A solution is made up of 0.15 grams of sodium chloride in 1 liter of water. For this solution, the solvent is water.
- A solution is made up of 0.15 grams of sodium chloride in 1 liter of water. For this solution, the solute is sodium chloride.
- If you place 5 moles of sodium chloride and 4 moles of sucrose into 11 moles of water, the molar fraction of sodium chloride would be 0.25.
- A way to express concentration that provides the moles of solute per liter of solution is molarity.
Explanation:
Hello,
This is about a concentration units set of questions spelled out as shown below:
- The expression of concentration that provides the moles of solute per kilograms of solvent is molality.
In this case, molality ([tex]m[/tex]) is defined as the ratio between the moles of the solute and the mass of the solvent in kilograms only:
[tex]m=\frac{n_{solute}}{m_{solvent}} [=]\frac{mol}{kg}[/tex]
- A solution is made up of 0.15 grams of sodium chloride in 1 liter of water. For this solution, the solvent is water.
In this case, since the sodium chloride is both naturally solid and ionic, it tends to dissociate in aqueous solution which works as a media to allow the solution process, that is why water is the solvent.
- A solution is made up of 0.15 grams of sodium chloride in 1 liter of water. For this solution, the solute is sodium chloride.
In this case, and considering the previous statement, since the molecules of the sodium chloride are dissociated when added to the water (solvent) it is considered as the solute.
- If you place 5 moles of sodium chloride and 4 moles of sucrose into 11 moles of water, the molar fraction of sodium chloride would be 0.25.
In this case, the molar fraction is computed via the ratio between the moles of the sodium chloride and the total moles as shown below:
[tex]x_{NaCl}=\frac{n_{NaCl}}{n_{total}}=\frac{5mol}{5mol+4mol+11mol} =0.25[/tex]
- A way to express concentration that provides the moles of solute per liter of solution is molarity.
In this case, molarity ([tex]M[/tex]) is defined as the ratio between the moles of the solute and the volume of the solution in liters only:
[tex]M=\frac{n_{solute}}{V_{solution}} [=]\frac{mol}{L}[/tex]
Best regards.
