For this case we must find the value of "x" of the following expression:
[tex]e^{3x + 6} = 8[/tex]
We apply Neperian logarithm to both sides of the equation:
[tex]3x + 6 = ln (8)[/tex]
Subtracting 6 from both sides of the equation:
[tex]3x = ln (8) -6[/tex]
Dividing by 3 on both sides of the equation:
[tex]x = \frac {ln (8) -6} {3}[/tex]
Answer:
Option A
