The space shuttle releases a space telescope into orbit
around the earth. The telescope goes from being
stationary to traveling at a speed of 1700 m/s in 25
seconds. What is the acceleration of the satellite?

Respuesta :

Answer: [tex]68 m/s^{2}[/tex]

Step-by-step explanation:

The acceleration [tex]a[/tex] of the satellite can be calculated by the following equation:

[tex]V_{f}=V_{o}+at[/tex]

Where:

[tex]V_{f}=1700 m/s[/tex] is the final speed of the satellite

[tex]V_{o}=0[/tex] is the initial speed of the satellite (it was "stationary" before the release)

[tex]t=25 s[/tex] is the time

Isolating [tex]a[/tex]:

[tex]a=\frac{V_{f}}{t}[/tex]

[tex]a=\frac{1700 m/s}{25 s}[/tex]

Finally:

[tex]a=68 m/s^{2}[/tex]