) Given the following balanced equation, determine the rate of reaction with respect to [O2]. If the rate of formation of O2is 7.78 × 10-1M/s, what is the rate of the loss of O3

Respuesta :

Answer:

Rate of the reaction is 0.2593 M/s

-0.5186 M/s is the rate of the loss of ozone.

Explanation:

The rate of the reaction is defined as change in any one of the concentration of reactant or product per unit time.

[tex]2O_3\rightleftharpoons 3O_2[/tex]

Rate of formation of oxygen : [tex]7.78\times 10^{-1} M/s[/tex]

Rate of the reaction(R) =[tex]\frac{-1}{2}\frac{d[O_3]}{dt}=\frac{1}{3}\frac{d[O_2]}{dt}[/tex]

[tex]R=\frac{1}{3}\frac{d[O_2]}{dt}[/tex]

Rate of formation of oxygen=3 × (R)

[tex]7.78\times 10^{-1} M/s=3\times R[/tex]

Rate of the reaction(R): [tex]0.2593 M/s[/tex]

Rate of the reaction is 0.2593 M/s

Rate of disappearance of the ozone:

[tex]R=-\frac{1}{2}\frac{d[O_3]}{dt}[/tex]

[tex]\frac{d[O_3]}{dt}=-2\times R=-2\times 0.2593\times M/s=-0.5186M/s[/tex]

-0.5186 M/s is the rate of the loss of ozone.