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An electron and a proton have charges of an equal magnitude but opposite sign of 1.6 x 10-19 C. If an electron and proton in a hydrogen atom are separated by a distance of 5 x 10-11 m, (a) what is the magnitude of the force exerted on the electron by the proton?

Respuesta :

Answer:

9.216 x 10^-8 N

Explanation:

q1 = 1.6 x 10^-19 C

q2 = - 1.6 x 10^-19 C

r = 5 x 10^-11 m

(a) The electrostatic force is given by

F = k q1 q2 / r^2

F = ( 9 x 10^9 x 1.6 x 10^-19 x 1.6 x 10^-19) / (5 x 10^-11)^2

F = 9.216 x 10^-8 N

This force is attractive in nature, as both the charges are opposite in nature.

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