Respuesta :
Answer:
2.282 × [tex]10^{18}[/tex] photons strike
Explanation:
Given data
average intensity = 1.00 kJ·s−1·m−2
wavelength = 510.0 nm
area = 8.90 cm²
to find out
how many photons strike
solution
we know energy of 1 photon i.e
= hc/ wavelength = 6.626 × [tex]10^{-34}[/tex] × 3 [tex]10^{8}[/tex] / 510 [tex]10^{-9}[/tex]
energy of 1 photon = 3.9 × [tex]10^{-19}[/tex] J
so now we know no of joules hitting is 8.90 cm²/sec
i.e = 1.00 kJ × 8.90 cm²
= 1000 × 8.90 [tex]10^{-4}[/tex]
= 0.8900 J
so number of photon is
N = 0.8900 / 3.9 × [tex]10^{-19}[/tex]
N = 2.282 × [tex]10^{18}[/tex]
2.282 × [tex]10^{18}[/tex] photons strike
