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A closed loop conductor with radius 2.0 m is located in a changing magnetic field. If the maximum emf induced in the loop is 2.0 V, what is the maximum rate at which the magnetic field strength is changing if the magnetic field is oriented perpendicular to the plane in which the loop lies?

Respuesta :

Answer:

0.159 Tesla per second

Explanation:

r = 2 m, e = 2 V,

Let the rate of magnetic field changing is dB / dt.

By use of Farady's law of electromagnetic induction

e = rate of change of magnetic flux

e = dФ /dt

e = A x dB / dt

2 = 3.14 x 2 x 2 x dB / dt

dB / dt = 0.159 Tesla per second

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