Answer : The number of moles of A remains are, 2.00 mole
Explanation :
As we are given that,
Number of moles of solid A = 4.80 mole
Volume of container = 1.00 L
Concentration of A = [tex]\frac{4.80mole}{1.00L}=4.80mole/L[/tex]
Concentration of B = 1.40 M
The moles of B in 1 liter of solution = [tex]1.40mole/L\times 1L=1.40mole[/tex]
When the volume is doubled then we are using volume 2 L instead of 1 L.
The moles of B in 2 liter of solution = [tex]1.40mole/L\times 2L=2.80mole[/tex]
The balanced chemical reaction is,
[tex]A(s)\rightleftharpoons B(g)+C(g)[/tex]
initial conc. 4.80 0 0
At eqm. (4.80-2.80) 2.80
The moles of A remains = 4.80 - 2.80 = 2.00 mole
Therefore, the number of moles of A remains are, 2.00 mole
