Answer:
The perimeter of ∆ABC is 32.44 units, and its area is 30 square units....
Step-by-step explanation:
The perimeter is the sum of three distances.
To find the distances BC, CD, DB use the distance formula:
D=√(y2-y1)^2+(x2-x1)^2
We have given A(2, 8), B(16, 2), and C(6, 2).
AB= √(16-2)^2+(2-8)^2
AB= √(14)^2+(-6)^2
AB=√196+36
AB=√232 = 15.23
BC=√(6-16)^2+(2-2)^2
BC=√(-10)^2+0
BC=√100 = 10
CA = √(2-6)^2+(8-2)^2
CA=√(-4)^2+(6)^2
CA=√16+36
CA=√52 = 7.21
Perimeter = AB+BC+CA
Perimeter = 15.23+10+7.21
Perimeter = 32.44 units
For the area BC is the parallel to x-axis
area = (1/2)base * height
=(1/2)10*(ya-yb)
=(1/2)10*(8-2)
=(1/2)10*6
=30 unit²
The perimeter of ∆ABC is 32.44 units, and its area is 30 square units....
Answer:
perimeter of ∆ABC is 32.44 units, and its area is 30 square units
Step-by-step explanation:
plato
