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Consider the following reaction, equilibrium concentrations, and equilibrium constant at a particular temperature. Determine the equilibrium concentration of H2O(g). C2H4(g) + H2O(g) ↔ C2H5OH(g) Kc = 9.0 × 103 [C2H4]eq = 0.015 M [C2H5OH]eq = 1.69 M

Respuesta :

Answer:  The equilibrium concentration of H2O(g) is 12.52  x [tex]10^{-3}[/tex]

Explanation:   The given equilibrium reaction is -

[tex]C_{2}H_{4}(g) + H_{2}O(g) \rightleftharpoons  C_{2}H_{5}OH(g)[/tex]

Equilibrium constant is the ratio of concentration of the products to the reactants.

Mathematically, it can be written as-

 Kc =  [tex][C_{2}H_{5}OH(g)][/tex]  /  [tex][C_{2}H_{4}][/tex]   [tex] [H_{2}O][/tex]  

Given values are -

Kc = 9.0 x [tex]10^{3}[/tex]

[tex][C_{2}H_{5}OH(g)][/tex] = 1.69M

[tex][C_{2}H_{4}][/tex] = 0.015M

Susbtituting these values in the equation we get

9.0 x [tex]10^{3}[/tex] = 1.69M / 0.015M [tex] [H_{2}O][/tex]  

[tex] [H_{2}O][/tex]   = 1.69M / 0.015M x  9.0 x [tex]10^{3}[/tex]

[tex] [H_{2}O][/tex]  = 12.52  x [tex]10^{-3}[/tex]

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