Answer:
desired temperature comes out to be equal to 293 K
Explanation:
M =20 g/ mol
= 0.02 kg/mol
γ = 1.67
R is (gas constant) = 8.314 J/ mol K
we know that,
[tex]v = \sqrt{\dfrac{\gamma R T}{M} }\\ v^2 = {\dfrac{\gamma R T}{M}\\[/tex]
[tex]451^2 = {\dfrac{1.67\times 8.314 \times T}{0.02}[/tex]
[tex]T=293 K[/tex]
hence the desired temperature comes out to be equal to 293 K.
