Answer:
The water will flow at a speed of 3,884 m/s
Explanation:
Torricelli's equation
v = [tex]\sqrt{2gh}[/tex]
*v = liquid velocity at the exit of the hole
g = gravity acceleration
h = distance from the surface of the liquid to the center of the hole.
v = [tex]\sqrt{2*9,8m/s^2*0,77m}[/tex] = 3,884 m/s
We have that for the Question"A large container, 120 cm deep is filled with water. If a small hole is punched in its side 77.0 cm from the top, at what initial speed will the water flow from the hole" it can be said that initial speed the water flow from the hole is
From the question we are told
A large container, 120 cm deep is filled with water. If a small hole is punched in its side 77.0 cm from the top, at what initial speed will the water flow from the hole? Please use a equation and explain every step
Generally the equation for the water flow speed is mathematically given as
[tex]v=\sqrt(2gh)\\\\v=\sqrt{2*9.8*0.77}[/tex]
v=3.88m/s
Therefore
initial speed the water flow from the hole is
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