Answer:
1.28 x 10^5 Pa
Explanation:
The absolute pressure at the bottom of the tank of water is given by:
[tex]p= p_0 + \rho g h[/tex]
where
[tex]p_0 = 1.03 \cdot 10^5 Pa[/tex] is the atmospheric pressure
[tex]\rho = 1000 kg/m^3[/tex] is the water density
g = 9.8 m/s^2 is the acceleration of gravity
h = 2.50 m is the heigth of the column of water
Substituting into the formula, we find
[tex]p=1.03\cdot 10^5 +(1000)(9.8)(2.50)=1.28\cdot 10^5 Pa[/tex]
