Answer:
a)13 bits
b)15 bits
Explanation:
a)
It takes 10 bits to address within a 1024-word page because 1024= 2^10.
Since the logical address space is 8 = 2^3 pages,
We will add 10 bits for 1024 words
10 + 3 = 13 bits must be the logical addresses.
b)
There are 32 = 2^5 physical pages.
We will add 10 bits for 1024 words
Similarly, physical addresses are 5 + 10 = 15 bits long .
