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If A, B, and Care 2x2 matrices; and det(A) = -2, det(B) = -3, and det(C)=-4 then compute: det(4C^TA^-1 C^TB^3) = 0 Official Time: 12:46:13 SUBMIT AND MARK SAVE AND CLOSE

Respuesta :

Answer with explanation:

|A| = -2

|B|= -3

|C| = -4

[tex]|4 C^TA^{-1}C^TB^{3}|=4 |C||A|^{-1}|C||B|^3, \text{as}|C^T|=|C|,|A^n|=A^n\\\\=4 \times (-4) \times (-2)^{-1} \times (-4) \times (-3)^3\\\\=4 \times (-4) \times \frac{-1}{2} \times (-4) \times (-27)\\\\=-1728 \times \frac{-1}{2} \\\\=864[/tex]