Answer:
120°
Step-by-step explanation:
Let there be a triangle ABC where ∠B is 80 and ∠C is 40
The rays p and q bisects the two angles and intersect at point O.
Now ∠OBC = 40°
∠OCB = 20°
Also we know that the sum of all the three angles of any triangle is 180
Hence
∠COB + ∠OBC + ∠OCB = 180°
∠COB +40° + 20° = 180°
∠COB =180° - 40° -20°
∠COB = 120°
Hence the obtuse angle formed by the bisectors of these two angles is 120°
