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At the beginning of an experiment, the concentration of nitrogen dioxide in a reaction vessel was 0.1103 mol/L. After 65.0 s, the concentration decreased to 0.1076 mol/L. What is the average rate of decomposition of NO2 during this time interval, in mol/(L ∙ s)?

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Answer:

-4.15*[tex]10^{-5}mol/(L.s)[/tex]

Explanation:

Average rate            = [tex]\frac{final concentration -initial concentration}{change in time} = \frac{0.1076mol/L-0.1103mol/L}{65s}=-4.15.10^{-5}mol/(L.s)[/tex]

The rate is negative because it is a decomposition and our focus is the reactant which is depleting.

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