The Montanez family is a family of four people. They have used 3,485.78 gallons of water so far this month. They cannot exceed 7,250.50 gallons per month during the drought season. Write an inequality to show how much water just one member of the family can use for the remainder of the month, assuming each family member uses the same amount of water every month.

The Montanez family cannot use more than 7250.50 gallons, this means that they can use less than or equal to 7250.50 gallons, this tells you which sign to use. The variable x can be used to describe how much water they have left to use and then you add 3,485.78 gallons to x.

x + 3485.78 ≤ 7250.50 This inequality means that the amount of water the family has yet to use added to 3485.78 gallons cannot exceed 7250.50 gallons.

Next, you simplify the inequality using the property of inequalities.

x ≤ 7250.50 - 3485.78

x ≤ 3764.72

yogeshkumar49685 yogeshkumar49685 · Answer 2 · 2022-06-24T20:30:12+02:00

The required inequality is x<941.18 for the Montanez family if they have used 3485.78 gallons of water.

What is inequality?

It is also a relationship between variables but this is in greater than , less than, greater than or equal to , less than or equal to is used.

How to form an inequality?

Let the water used by a member be x

so

x*4=7250.50-3485.78

4x=3764.72

x=941.18

Hence one member can only use 941.18 gallons of water in the month.

Learn more about inequality at https://brainly.com/question/11613554

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