Answer:
The energy of photon, [tex]E=8\times 10^{-15}\ J[/tex]
Explanation:
It is given that,
Voltage of anode, [tex]V=50\ kV=50\times 10^3\ V=5\times 10^4\ V[/tex]
We need to find the maximum energy of the photon of the x- ray radiation. The energy required to raise an electron through one volt is called electron volt.
[tex]E=eV[/tex]
e is charge of electron
[tex]E=1.6\times 10^{-19}\times 5\times 10^4[/tex]
[tex]E=8\times 10^{-15}\ J[/tex]
So, the maximum energy of the x- ray radiation is [tex]8\times 10^{-15}\ J[/tex]. Hence, this is the required solution.
