Answer:
The equilibrium temperature of the surface of the moon can be found by the formula as follows:
[tex]T=(\frac{K_s(1-alebdo)}{4 \sigma})^{\frac{1}{4}} [/tex]
Where [tex]K_s = 1366 W/m^2[/tex] is the solar constant and [tex]\sigma = 5.67 \times 10^ {-8}W/m^2K^{-4} [/tex] is the Stefan's Boltzmann constant.
[tex]T=(\frac{1366(1-0.08)}{4\times 5.67 \times 10^ {-8}})^{\frac{1}{4}} = (55.41\times 10^8)^{\frac{1}{4}} = 272.7 K=273 K[/tex]
Thus, the equilibrium temperature of the surface of the moon is 273 K.
