contestada

Consider an electromagnet (e.g. in a relay) that is operated at 50 A. If the inductance of the coil is 100 H and the time to switch-off the current is 1 ms, what voltage will be developed across its terminals?

Respuesta :

Answer:

5 x 10⁶ volts

Explanation:

[tex]i_{o}[/tex] = Initial value of current = 50 A

[tex]i_{f}[/tex] = Final value of current = 0 A

Δt = time taken = 1 ms = 0.001 s

[tex]V[/tex]  = Voltage developed across the terminals

Voltage developed across the terminals is given as

[tex]V = \frac{L(i_{f} - i_{o})}{\Delta t}[/tex]

[tex]V = -\frac{(100)(0 - 50)}{0.001}[/tex]

[tex]V[/tex]  = 5 x 10⁶ volts

Otras preguntas