Answer:
34066.6 hp
Explanation:
We have given efficiency=33%=0.33
[tex]efficiency=\frac{W}{Q_1}[/tex]
[tex]Q_1=\frac{W}{efficiency}[/tex]
[tex]Q_1=\frac{14600}{0.33}=44242.4242\ hp[/tex]
we know that [tex]W=Q_1-Q_2[/tex]
[tex]Q_2=Q_1-W[/tex]
=44242.4242-14600=29642.4242HP
so the value of [tex]Q_2[/tex] the rate of heat of rejection is 29642.4242 hp
