Answer:
0.04 m³.
Explanation:
where, P is the pressure of the gas in atm.
V is the volume of the gas in L.
n is the no. of moles of the gas in mol.
R is the general gas constant,
T is the temperature of the gas in K.
(P₁V₁) = (P₂V₂).
V₁ = 0.025 m³, P₁ = 1.5 x 10⁶ Pa,
V₂ = ??? m³, P₂ = 0.95 x 10⁶ Pa.
∴ V₂ = (P₁V₁)/(P₂) = (0.025 m³)(1.5 x 10⁶ Pa)/(0.95 x 10⁶ Pa) = 0.04 m³.
Answer: The final volume of the container is [tex]0.040m^3[/tex]
Explanation:
To calculate the new volume, we use the equation given by Boyle's law. This law states that pressure is inversely proportional to the volume of the gas at constant temperature.
The equation given by this law is:
[tex]P_1V_1=P_2V_2[/tex]
where,
[tex]P_1\text{ and }V_1[/tex] are initial pressure and volume.
[tex]P_2\text{ and }V_2[/tex] are final pressure and volume.
We are given:
[tex]P_1=1.50\times 10^6Pa\\V_1=0.0250m^3\\P_2=0.950\times 10^6\\V_2=?m^3[/tex]
Putting values in above equation, we get:
[tex]1.50\times 10^6Pa\times 0.0250m^3=0.950\times 10^6Pa\times V_2\\\\V_2=\frac{1.50\times 10^6\times 0.0250}{0.950\times 10^6}=0.040m^3[/tex]
Hence, the final volume of container is [tex]0.040m^3[/tex]
