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A conductor is formed into a loop that encloses an area of 1m^2. The loop is oriented at a angle 30 degree with the xy plane. A varying magnetic field is oriented parallel to the z axis. If the maximum emf induced in the loop is 10v, what is the maximum rate at which the magnetic field strength is changing?

Respuesta :

Answer:

[tex]\frac{dB}{dt} = 11.55 T/s[/tex]

Explanation:

As we know that flux of magnetic field from the closed loop is given by

[tex]\phi = BAcos30[tex]

now by Faraday's law we know

[tex]EMF = \frac{d\phi}{dt}[/tex]

now we will have

[tex]EMF = Acos30\frac{dB}{dt}[/tex]

now we have

[tex]A = 1 m^2[/tex]

EMF = 10 Volts

[tex]10 = 1 (cos30)\frac{dB}{dt}[/tex]

[tex]\frac{dB}{dt} = \frac{20}{\sqrt3}[/tex]

[tex]\frac{dB}{dt} = 11.55 T/s[/tex]

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