True
What is the divisibility test of 4?
If a number's last two digits are divisible by 4, the number is a multiple of 4 and totally divisible by 4.
Solving the problem.
6m(2m+10) = 6m cannot be said to be always divisible by 4 but is divisible by 2 as 6m = 2*3m
(2m+10) cannot say if it is divisible by but can say is divisible by 2 as we can take 2 commons from both the integer and rewrite it as 2*(m+5).
Hence multiplying both the numbers we get = 2*3m*2(m+5) and now we group 2's together we get 4*3m*(m+5), as the whole number is multiplied by 4 it is at least divisible by 4 once.
Hence proved that 6m(2m+10) is divisible by 4 and the answer is true.
learn more about Divisibility here
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