Answer:
The distance is 54.6 m
Explanation:
Given that,
Mass = 2.0 kg
Frictional coefficient = 0.21
Initial velocity = 15 m/s
We need to calculate the acceleration
Using formula of frictional force
[tex]F = \mu mg[/tex]
[tex]F=0.21\times2.0\times9.8[/tex]
[tex]F = 4.12\ N[/tex]
We need to calculate the acceleration
[tex]F = ma[/tex]
[tex]a = \dfrac{F}{m}[/tex]
[tex]a =\dfrac{4.12}{2.0}[/tex]
[tex]a=2.06\ m/s^2[/tex]
We need to calculate the initial velocity
Using equation of motion
[tex]v^2=u^2-2as[/tex]
Put the value
[tex]0=15^2-2\times2.06\times s[/tex]
[tex]s = \dfrac{15^2}{2\times2.06}[/tex]
[tex]s=54.6\ m[/tex]
Hence, The distance will be 54.6 m.
