Answer:
Magnitude of force, F = 11 Newtons
Explanation:
Charge 1, [tex]q_1=5.3\ \mu C=5.3\times 10^{-6}\ C[/tex]
Charge 2, [tex]q_2=11.2\ \mu C=11.2\times 10^{-6}\ C[/tex]
The separation between the charges is, r = 0.22 m
We have to find the magnitude of the force between two point charges. It can be calculated using the formula as :
[tex]F=k\dfrac{q_1q_2}{r^2}[/tex]
[tex]F=9\times 10^9\times \dfrac{5.3\times 10^{-6}\ C\times 11.2\times 10^{-6}\ C}{(0.22\ m)^2}[/tex]
F = 11.03 N
or
F = 11 Newtons
Hence, this is the required solution.
