Answer:
Number of electrons, [tex]n=2.7\times 10^{19}[/tex]
Explanation:
It is given that,
Charge, q = 4.33 C
We need to find the number of electrons that make 4.33 C of charge. According to quantization of charge as :
[tex]q=ne[/tex]
n = number of electrons
e = electron's charge
[tex]n=\dfrac{q}{e}[/tex]
[tex]n=\dfrac{4.33\ C}{1.6\times 10^{-19}\ C}[/tex]
[tex]n=2.7\times 10^{19}[/tex]
So, the number of electrons are [tex]2.7\times 10^{19}[/tex] Hence, this is the required solution.
