What is the maximum speed with which a 1200-kg car can round a turn of radus 84.0 m on a flat road if the coefficient of static friction between tires and road is 0.60. Express your answer to two significant figures and include the apprepriate units.

Respuesta :

Explanation:

It is given that,

Mass of the car, m = 1200 kg

Radius of circular path, r = 84 m

The coefficient of static friction between tires and road is 0.60

Static friction is given by :

[tex]f=\mu N=\mu mg[/tex]..............(1)

When an object is moving in a circular path, the centripetal force will act on it. It is given by :

[tex]F=\dfrac{mv^2}{r}[/tex]

Let v is the maximum speed of the car. From equation (1) and (2) as :

[tex]v=\sqrt{\mu gr}[/tex]

g = acceleration due to gravity

[tex]v=\sqrt{0.6\times 9.8\ m/s^2\times 84\ m}[/tex]

v = 22.22 m/s

or

v = 22 m/s

Hence, this is the required solution.