In boot camp, a cadet must use a rope swing to cross an obstacle without
falling into the water hazard below. Unfortunately, they miss the platform on
the other side and swing back to where they started. If it takes the cadet 4.5
seconds to swing from one side of the obstacle to the other and back, how
long is the rope swing? Use the formula:
T=2pie ,square root L over 9.8

Respuesta :

Answer:

5 meters

Step-by-step explanation:

A P E X

The length of the rope swing for the considered case is found being of 5 meters approximately.

How to find the period of oscillation of a simple gravity pendulum?

If we've got:

  • Gravity constant = g
  • Length of pendulum = L

Then, we get:

[tex]T \approx 2\pi \sqrt{\dfrac{L}{g}}[/tex]

This is the period of oscillation, the time taken for a complete cycle in a simple gravity pendulum.

Using the above formula, as for this case, we're specified that:

  • Gravity constant = 9.8 m/s²  = g
  • Time taken for complete swing (back to forth and then again back) = 4.5 seconds. = T

Then, the length of the rope is obtained as:

[tex]T \approx 2\pi \sqrt{\dfrac{L}{g}} \: \rm \:sec\\\\L = \dfrac{T^2g}{4\pi^2} \: \rm meters\\\\\L \approx \dfrac{(4.5)^2\times 2\times (9.8)}{4\pi^2} \approx 5 \: \rm meters[/tex]

Thus, the length of the rope swing for the considered case is found being of 5 meters approximately

Learn more about length and period oscillation of a pendulum here:

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