Explanation:
It is given that,
Speed of a wave, v = 251 m/s
Wavelength of the wave, λ = 5.1 cm = 0.051 m
(1) The frequency of the wave is given by :
[tex]\nu=\dfrac{v}{\lambda}[/tex]
[tex]\nu=\dfrac{251\ m/s}{0.051\ m}[/tex]
[tex]\nu=4921.56\ Hz[/tex]
(2) Angular frequency of the wave is given by :
[tex]\omega=2\pi\nu[/tex]
[tex]\omega=2\pi\times 4921.56\ Hz[/tex]
[tex]\omega=30923.07\ rad/s[/tex]
(3) The period of oscillation is given by T as :
[tex]T=\dfrac{1}{\nu}[/tex]
[tex]T=\dfrac{1}{4921.56}[/tex]
T = 0.000203 seconds
or
T = 0.203 milliseconds
Hence, this is the required solution.
