These tables represents a quadratic function with a vertex at (0,3) what is the average rate of change for the interval from x=8 to x=9

There are a few ways to do it; the easiest is just to follow the pattern of taking away two from the average.
The next lines of the table are
6 to 7 -13
7 to 8 -15
8 to 9 -17
Answer: C. -17
Let's find the equation and do it that way.
We have a vertex at (0,3) so we can fill out the vertex form a bit. In general for vertex (p,q) it's
y = a(x-p)^2+q
We have
f(x) = ax^2 + 3
f(1) = 2
a+3 =2
a = -1
So we found our equation,
y = -x^2 + 3
Let's check it at x=5, y=-5^2+3=-25+3=-22, good
We want the rate of change from 8 to 9, which is
[tex]r = \dfrac{f(9)-f(8)}{9-8}=f(9)-f(8)=-9^2 - -8^2 = -17[/tex]
Answer: -17 again, that checks
The average rate of change for the interval from x=8 to x=9 is -17.
The correct option is (C)
Graph is a mathematical representation of a network and it describes the relationship between lines and points.
We have a vertex at (0,3).
In general let us take vertex (p,q) then
y = a(x-p)²+q
We have,
f(x) = ax² + 3
as x=1, f(x)=2
so,
f(1) = 2
a+3 =2
a = -1
Now, the equation
y = -x² + 3
Thus, the rate of change from 8 to 9
= f(9)-f(8)/9-8
= -9²-(-8)²
=-81+64
=-17
Hence, the average rate of change for the interval from x=8 to x=9 is -17.
Learn more about this concept here:
https://brainly.com/question/14372714
#SPJ2