Answer:
[tex]\large\boxed{x=-\dfrac{2}{3}\ or\ x=1}[/tex]
Step-by-step explanation:
[tex]3x^2-x-2=0\\\\3x^2+2x-3x-2=0\\\\x(3x+2)-1(3x+2)=0\\\\(3x+2)(x-1)=0\iff3x+2=0\ \vee\ x-1=0\\\\3x+2=0\qquad\text{subtract 2 from both sides}\\3x=-2\qquad\text{divide both sides by 3}\\x=-\dfrac{2}{3}\\\\x-1=0\qquad\text{add 1 to both sides}\\x=1[/tex]
