Respuesta :

Answer:

D) arccsc (x) = arcsin (1/x)

Step-by-step explanation:

Here's how you can prove it: Consider a right triangle with hypotenuse 1 and a side length 1/x.  If θ is the angle opposite of 1/x, then:

sin θ = 1/x

and

csc θ = x

Solving for θ:

θ = arcsin (1/x)

θ = arccsc (x)

Therefore:

arccsc (x) = arcsin (1/x)

The trigonometric function gives the ratio of different sides of a right-angle triangle.The correct option is D, arc cosec (x) = arc sin (1/x).

What are Trigonometric functions?

The trigonometric function gives the ratio of different sides of a right-angle triangle.

[tex]\rm Sin \theta=\dfrac{Perpendicular}{Hypotenuse}\\\\\\Cos \theta=\dfrac{Base}{Hypotenuse}\\\\\\Tan \theta=\dfrac{Perpendicular}{Base}\\\\\\Cosec \theta=\dfrac{Hypotenuse}{Perpendicular}\\\\\\Sec \theta=\dfrac{Hypotenuse}{Base}\\\\\\Cot \theta=\dfrac{Base}{Perpendicular}\\\\\\[/tex]

where perpendicular is the side of the triangle which is opposite to the angle, and the hypotenuse is the longest side of the triangle which is opposite to the 90° angle.

Assume a right-angled triangle such that the hypotenuse of the triangle is of 1 unit, while the side opposite to angle A measures 1/x units, as shown in the triangle below. Also, the measure of the ∠A is θ. Therefore, we can write,

sin θ = 1/x

cosec θ = x

Solving both the ratios for θ, we will get,

θ = arc sin (1/x)

θ = arc cosec (x)

Equating the two equations formed above together, therefore, we can write,

θ = θ

arc cosec (x) = arc sin (1/x)

Learn more about Trigonometric functions:

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