Respuesta :

r3t40

[tex]

R_1=20\Omega \\

R_2=30\Omega \\

R_3=30\Omega \\

U=2V \\ \\

R_{12}=\dfrac{1}{R_1}+\dfrac{1}{R_2}=\dfrac{R_1R_2}{R_1+R_2}=15\Omega \\

R_{123}=\dfrac{R_{12}R_3}{R_{12}+R_3}=10\Omega \\

I=\dfrac{U}{R_{123}}=\boxed{0.2A}

[/tex]

Hope this helps.

r3t40