For this case we have the following quadratic function:
[tex]f (x) = x ^ 2 + x-6[/tex]
We must find its roots. We can factor, looking for two numbers that when added to +1 and multiplied by -6. These are:
+3 and -2
[tex]+ 3-2 = 1\\(+3) * (- 2) = - 6[/tex]
Then, the factored form is:
[tex](x + 3) (x-2) = 0[/tex]
So, the roots are:
[tex]x_ {1} = - 3\\x_ {2} = 2[/tex]
Answer:
[tex]x_ {1} = - 3\\x_ {2} = 2[/tex]
