Respuesta :

You have to use the formula

[tex]a^2-b^2 = (a+b)(a-b)[/tex]

twice: we have

[tex]x^4-81 = (x^2+9)(x^2-9) = (x^2+9)(x+3)(x-3)[/tex]

So, we have

[tex]\dfrac{x^4-81}{x+3} = \dfrac{(x^2+9)(x+3)(x-3)}{x+3} = (x^2+9)(x-3)[/tex]

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