Check the picture below.
so we have 3 rectangles and 1 semicircle.
let's recall that the area of a circle = A = πr², so then the area of a semi-circle is πr²/2.
let's get the area of all figures, sum them up, and that's the area of the composite.
[tex]\bf \stackrel{\textit{top rectangle}}{(2\cdot 5)}+\stackrel{\textit{middle rectangle}}{(4\cdot 11)}+\stackrel{\textit{bottom rectangle}}{(9\cdot 2)}+\stackrel{\textit{semicircle}}{\cfrac{25\pi }{2}} \\\\\\ 10+44+18+12.5\pi \implies 72+12.5\pi \qquad \approx\qquad 111.27[/tex]
