ANSWER
[tex]P( \bar E) =\frac{14}{15} [/tex]
EXPLANATION
The sample space is S={1,23,4,5,...60}
n(S)=60
The multiples of 13 are:
E={13,26,39,52}
n(E)=4
Probability of choosing a picture that is a multiple of 13 is
[tex]P(E)= \frac{n(E)}{n(S)} [/tex]
[tex]P(E)= \frac{4}{60} [/tex]
Probability of choosing a picture that is NOT a multiple of 13 is
[tex]P( \bar E)= 1 - \frac{4}{60} = \frac{56}{60} = \frac{14}{15} [/tex]
