What is the average velocity of atoms in 1.00 mol of argon (a monatomic gas) at 275 K? For m, use 0.0399 kg. (1 point)

Respuesta :

The velocity of the argon atoms has been 414.6155 m/s.

The average velocity of the atom has been the speed possessed by the atom at the certain temperature.

The average velocity of the gas has been given by:

[tex]v=\sqrt{\dfrac{3nRT}{m} }[/tex]

Computation for the velocity of argon atoms

The moles of argon have been, [tex]n=1[/tex]

The Boltzmann constant has been, [tex]R=8.31\;\rm J/mol.K[/tex]

The temperature of gas has been, [tex]T=275\;\rm K[/tex]

The mass of the gas has bee, [tex]m=0.0399\;\rm kg[/tex]

Substitute the values for the velocity, v, of argon atoms as:

[tex]v=\sqrt{\dfrac{3\;\times\;1\;\;\times\;8.13\;\times\; 275}{0.0399} }\\v= \sqrt{171,906.015}\\v= 414.6155\;\rm m/s[/tex]

The velocity of the argon atoms has been 414.6155 m/s.

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