Respuesta :

Answer:

[tex]\log (3x)[/tex]

Step-by-step explanation:

The given logarithmic expression is:

[tex]\frac{1}{3}\log(3x)+ \frac{2}{3}\log(3x)[/tex]

This is the same as:

[tex]\frac{1}{3}\log(3x)+ \frac{1}{3}\log(3x)^2[/tex]

[tex]\frac{1}{3}(\log(3x)+ \log(3x)^2)[/tex]

We now apply the product rule to get:

[tex]\frac{1}{3}\log(3x)\times (3x)^2[/tex]

[tex]\frac{1}{3}\log (3x)^3[/tex]

We now apply the power rule to get;

[tex]\frac{3}{3}\log (3x)=\log (3x)[/tex]

Otras preguntas