Answer:
D. Zn → Zn²⁺ + 2e⁻, 2H⁺ + 2e⁻ → H₂.
Explanation:
- It is a redox reaction that is consisted of two half-reactions:
Oxidation reaction:
Zn losses 2 electrons and is oxidized to Zn²⁺:
Zn → Zn²⁺ + 2e⁻.
Reduction reaction:
H⁺ gains 1 electron and is reduced to H:
2H⁺ + 2e⁻ → H₂.
So, the right choice is: D. Zn → Zn²⁺ + 2e⁻, 2H⁺ + 2e⁻ → H₂.
