Answer:
The radius of circle L is [tex]7.8\ in[/tex]
Step-by-step explanation:
Remember that a line that passes through the center divide the circle into two equal parts
YV=VM=6 in
VL is perpendicular to YM
so
The triangle VLM is a right triangle
The radius is equal to LM ----> hypotenuse of the triangle VLM
Applying the Pythagoras Theorem
[tex]LM^{2}=VM^{2}+VL^{2}[/tex]
substitute the given values
[tex]LM^{2}=6^{2}+5^{2}[/tex]
[tex]LM^{2}=61[/tex]
[tex]LM=7.8\ in[/tex]
